Question
A particle is projected vertically upwards from ground. At time it is at A at a height h from ground and still going upwards. From A, it takes further t2 time to reach back to ground again. Show that
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Solution
Let,
Velocity with which the particle is projected from the ground be 'u'.
The particle takes time t1 to reach A and time t2 to reach the ground.
Thus, total time of flight of particle is t1 + t2.
Also the total time of fight =
On comparing the two, we get
The particle is at a height h from ground at time t1, which is given by
(ii) Maximum height attained is,
Velocity with which the particle is projected from the ground be 'u'.
The particle takes time t1 to reach A and time t2 to reach the ground.
Thus, total time of flight of particle is t1 + t2.
Also the total time of fight =
On comparing the two, we get
The particle is at a height h from ground at time t1, which is given by
(ii) Maximum height attained is,
