-->

Motion In Straight Line

Question
CBSEENPH11017209

The position of the particle at any instant is given by the equation

x = 3t2- 2.5t2 - 4.

what is the velocity and acceleration of particle at 3s?

Solution

The position of the particle is given by,
                x=3t-2.5t-4
Velocity of the particle at any instant is,
straight v equals dx over dt equals straight d over dt left parenthesis 3 straight t cubed minus 2.5 space straight t squared minus 4 right parenthesis
equals 9 straight t squared minus 5 straight t
space space therefore Velocity  at  t = 3s is, 
v(3) =  9(3)- 5 x 3 = 81 - 15 = 66 units 
Acceleration of the particle at any instant is, 
straight v equals dx over dt equals straight d over dt left parenthesis 9 straight t squared minus 5 straight t right parenthesis
equals space 18 straight t minus 5 
space space therefore  Acceleration at t = 3 s is,
a(3) = 18 x 3-5 = 54 - 5 = 49 units