Question
Plot position-time graph for uniform accelerated motion and show that area under v-t graph is equal to displacement of particle.
Solution
The velocity-time relation for uniform accelerated motion is given by,
v = u + at ...(1)
The position-time graph for uniform accelerated motion is oblique straight line.
Now area under v-t graph from t = 0 to t = t is = Area under segment AB
= Area of rectangle ACDO + Area of ∆ABC.
