-->

Motion In Straight Line

Question
CBSEENPH11017167

A car moving along a straight highway with speed of 126 km/hr is brought to a stop within a distance of 200 m. What is the retardation of the car (assumed uniform), and how long does it take for the car to stop?

Solution

Here,
Initial velocity, u = 126 km/hr = 35m/s
Final velocity, v = 0
Distance travelled, s = 200m 
Now using the equation of motion,
                      v2-u= 2as
Substituting the value of v, u and s we get, 
             (0)2-(35)= 2a x 200 
rightwards double arrow                       a = -3.0625 m/s

Time taken by the car to stop is given by, 
           straight t equals fraction numerator straight v minus straight u over denominator straight a end fraction equals fraction numerator 0 minus 35 over denominator negative 3.0625 end fraction equals 11.43 straight s