Question
A ball is thrown vertically upward and returns back to the hands of thrower in 6s. Find the velocity of throw and maximum height attained by the ball.
Solution
Let the ball be projected with velocity u from the ground.
Let us take upward direction positive and ground as reference point.
Thus,
Now, using the formula,
0 = 6u-176.4
i.e., u = 29.4 m/s
Let h be the maximum height attained by the ball.
Using third equation of motion, we have
(0)2 - (29.4)2 = 2 x(-9.8)h
h = 44.1 m, is the maximum height attained by the ball.
Let us take upward direction positive and ground as reference point.
Thus,
Now, using the formula,
0 = 6u-176.4i.e., u = 29.4 m/s
Let h be the maximum height attained by the ball.
Using third equation of motion, we have
(0)2 - (29.4)2 = 2 x(-9.8)h h = 44.1 m, is the maximum height attained by the ball.
