Question
A body is thrown up with velocity 39.2m/sec. What is the direction of velocity and acceleration at t = 0, t = 3, t = 4, t = 6?
Solution
Given, a body is thrown up with velocity = 39.2 m/s.
Acceleration due to gravity is acting vertically in a downward direction.
Acceleration, g = 9.8 m/s2
The body thrown in upward direction with velocity 39.2 m/s will take 4s to reach the maximum height.
At t = 0 and t = 3, the velocity is in upward direction.
At t = 4 sec velocity is zero and at t = 6 sec, velocity will be in downward direction.
