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Question
CBSEENSC10014709

(a) Define optical centre of a spherical lens.

(b) A divergent lens has a focal length of 20 cm. At what distance should an object of height 4 cm from the optical centre of the lens be placed so that its image is formed 10 cm away from the lens. Find the size of the image also.

(c) Draw a ray diagram to show the formation of image in above situation.

Solution
a) Optical centre is the point lying on the principal axis of a lens through which light passes through without undergoing any deviation.
b) Given,
Focal length, f = -20 cm
Height of the object, h1 = 4 cm
Image distance, v = -10 cm
To find: Object distance = ?
Size of the image, h2 = ?
Now, using the lens formula,

1 over straight f equals 1 over v minus 1 over u

space space space space space equals space fraction numerator negative 1 over denominator negative 10 end fraction minus fraction numerator 1 over denominator negative 20 end fraction

space space space space space equals space fraction numerator negative 1 over denominator 10 end fraction plus 1 over 20

space space space space space equals space fraction numerator negative 2 plus 1 over denominator 20 end fraction

space space space space space space equals fraction numerator negative 1 over denominator 20 end fraction

u space equals space minus 20 space c m
Therefore, object is at a distance of 20 cm on the left side of the lens.
Size of the image is given by,
straight h subscript straight i space equals space straight v over straight u space straight h subscript straight o

space space space space equals space fraction numerator negative 10 over denominator negative 20 end fraction space straight x space 4

space space space space equals space 2 space cm
c) The ray diagram is as given below: