Question
A submarine emits a SONAR pulse, which returns from an obstacle underwater cliff in 1.02 s. If the speed of sound in salt water is 1531 m/s, how far away is the cliff?
Solution
Given,
Time between transmission and detection of sonar pulse, = 1.02 s
Speed of sound in salt water, v= 1531 ms-2
Let, distance of the cliff be equal to d (say).
Then the distance travelecd by sound = 2d
Now, using the distance-time formula, we have
2d = speed of sound x time
= vt
= 1531 x 1.02 m
So, distance of the cliff, d =
