Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60 km/h?

Solution

G i v e n comma space M a s s space o f space t h e space b o d y comma space straight m space equals space 1500 space k g V e l o c i t y comma space space straight v space equals space 60 space k m divided by straight h space equals space fraction numerator 60 space cross times space 1000 space straight m over denominator 3600 space straight s end fraction space equals space 50 over 3 straight m divided by straight s

Work required to be done to stop the car,
W = Change in K.E. of the car

equals space 1 half m v squared space minus space 1 half straight m left parenthesis 0 right parenthesis squared space equals space 1 half m v squared equals space 1 half cross times 1500 space cross times space open parentheses 50 over 3 close parentheses squared space equals space 208333.3 space straight J.

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