A block of wood is kept on a table top. The mass of wooden block is 5 kg and its dimensions are 40 cm x 20 cm x 10 cm. Find the pressure exerted by the wooden block on the table top if it is made to lie on the table top with its sides of dimensions (i) 20 cm x 10 cm and (ii) 40 cm x 20 cm.
Mass of the wooden block = 5 kg
Dimensions of the block = 40 cm x 20 cm x 10 cm
Force exerted by the block on the table top,
F = Weight of block = mg = 5 x 9.8 = 49 N
(i) Let us consider the side of dimension 20 cm x 10 cm
Therefore,
Area = Length x Breadth = 20 cm x 10 cm
= 0.20 x 0.10 m = 0.02 m2
That is,
(ii) Consider the block lies on its side 40 cm x 20 cm,
Area = Length x Breadth
= 40 cm x 20 cm
= 0.40 m x 0.20 m = 0.08 m2
When the block lies on its side 40 cm x 20 cm, it exerts the same force F.