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Atoms And Molecules

Question
CBSEENSC9006123

A particle is thrown up vertically with a velocity of 50 m/s. Make a table showing the distance covered by the particle, the velocity and acceleration at the end of each second of its journey. Use this data to draw distance-time, velocity-time and acceleration-time graphs.

Solution

Displacement covered is s.
Velocity attained is given by,
             v = u - gt
Acceleration, a = -g
Given:
Initial velocity, u = 50 ms-1
Acceleration due to gravity, a = -10 ms-2

Time

Displacement

Distance

Velocity

Acceleration

0

1

2

3

4

5

6

7

8

9

10

0 m

45 m

80 m

105 m

120 m

125 m

120 m

105 m

80 m

45 m

0

0

45 m

80 m

105 m

120 m

125 m

130 m

145 m

170 m

205 m

250 m

50 ms–1

40 ms–1

30 ms–1

20 ms–1

10 ms–1

0

-10 ms–1

-20 ms–1

-30 ms–1

-40 ms–1

-50 ms–1

-10 m/s2

-10 m/s2

-10 m/s 2

-10 m/s2

-10 m/s 2

-10 m/s2

-10 m/s 2

-10 m/s-2

-10 m/s 2

-10 m/s 2

-10 m/s 2

Fig. (i) Distance-time graph.

Fig. (ii): Velocity-time graph


Fig. (iii) Acceleration-time graph.