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Atoms And Molecules

Question
CBSEENSC9006124

A particle is dropped from a tower 180 m high. How long does it take to reach the ground ? What is its velocity when it touches the ground ?

Solution

Given that, 
Distance from which the ball is dropped, s = -180 m (negative sign for downward displacement)
Initial velocity, u = 0 m/s
Acceleration due to gravity, g = - 10 m/s2
Using the second equation of motion, 
space space space space space space space space space space space space space space space space space space space space space straight s space equals space ut space plus space 1 half gt squared space
rightwards double arrow space space space space space space minus 180 space equals space 0 space minus space 1 half cross times 10 cross times straight t squared
rightwards double arrow space space space space space space space space space straight t squared space equals space fraction numerator 180 cross times 2 over denominator 10 end fraction space equals space 36 space
rightwards double arrow space space space space space space space space space space straight t space equals space 6 space seconds

Velocity space on space reaching space the space ground comma space

straight v space equals space straight u space plus space gt space

space space space equals space 0 space minus space 10 cross times 6

space space space equals space minus 60 space straight m divided by straight s
Negative space sign space indicates space that space the
space velocity space is space in space the space downward space direction. space