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Atoms And Molecules

Question
CBSEENSC9006113

A body is thrown vertically upwards and rises to a height of 10 m. Calculate (i) the velocity with which the body was thrown upwards and (ii) the time taken by the body to reach the highest point.

(Textbook Example 10.3)

Solution

Given,
Distance travelled,  s = 10 m
Final space velocity comma space straight v space equals space 0 space straight m divided by straight s
straight g space equals space minus 9.8 space straight m divided by straight s squared

straight i right parenthesis thin space Using space the space formula comma

space space space space space straight v squared space minus space straight u squared space equals space 2 gs space

rightwards double arrow space 0 squared space minus space straight u squared space equals space 2 cross times left parenthesis negative 9.8 right parenthesis cross times 10

rightwards double arrow space space straight u squared space equals space 196

rightwards double arrow space space straight u space equals space square root of 196 space equals space 14 space straight m divided by straight s

straight u space is space the space velocity space with space which space the space body space is space thrown space upwards.

ii right parenthesis thin space Again comma space using space the space formula

space space space space space space space space straight v space equals space straight u plus gt space

Time space taken space by space the space body space to space reach space the space highest space point comma

straight t space equals space fraction numerator straight v space minus straight u over denominator straight g end fraction space equals fraction numerator 0 minus 14 over denominator straight g end fraction equals space 1.43 space sec