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Home > Atoms And Molecules

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Atoms And Molecules

Question
CBSEENSC9006108
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Using the equation g = Gm/r2 and knowing the value of G, calculate the value of the acceleration due to gravity. Take the value of the mass of the earth = 6 x 1024 kg and radius = 6.4 x 106 m.

Solution
Short Answer

Given, 
Mass space of space the space earth comma space straight M space equals space 6 space cross times space 10 to the power of 24 space kg

Radius space of space the space Earth comma space straight R space equals space 6.4 space cross times space 10 to the power of 6 space straight m

Gravitational space constant comma space straight G space equals space 6.67 space cross times space 10 to the power of negative 11 end exponent space Nm squared divided by kg squared

Therefore space value space of space straight g space on space Earth comma
space space space therefore space space space space space straight g space equals space GM over straight R squared space

space space space space space space space space space space space space space space space space equals space fraction numerator 6.67 space cross times space 10 to the power of negative 11 end exponent space cross times space 6 space cross times space 10 to the power of 24 over denominator 6.4 space cross times space 10 to the power of 6 space cross times space 6.4 space cross times space 10 to the power of 6 end fraction straight m divided by straight s squared space

space space space space space space space space space space space space space space space space equals space 9.8 space straight m divided by straight s squared


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