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Atoms And Molecules

Question
CBSEENSC9006098

A sphere of mass 40 kg is attracted by a second sphere of mass 60 kg with a force equal to 4 x 10–5 N. If G = 6 x 10–11 Nm2/kg 2, calculate the distance between the two spheres.

Solution

Given,
Mass of the first sphere, m1 = 40 kg
Mass of the second sphere, m2 = 60 kg
Forcing acting between the bodies, F = 4 x 10–5 N
Gravitaional constant, G = 6 x 10–11 Nm2/kg2.
Now, using the formula, 
As space space space space space straight F space equals space straight G fraction numerator straight m subscript 1 straight m subscript 2 over denominator straight r squared end fraction
therefore space space space space straight r space equals space square root of fraction numerator Gm subscript 1 straight m subscript 2 over denominator straight F end fraction end root space equals space square root of fraction numerator 6 cross times 10 to the power of 11 cross times 40 cross times 60 over denominator 4 cross times 10 to the power of negative 5 end exponent end fraction end root space equals space square root of 36 space cross times space 10 to the power of negative 4 end exponent end root space equals space 6 space cross times space 10 to the power of negative 2 end exponent straight m
space space space space space space space equals space 6 space cross times space 10 to the power of negative 2 end exponent space cross times space 100 space cm space equals space 6 space cm. space Ans.


Therefore, the distance between the two spheres is 6 cm.