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Atoms And Molecules

Question
CBSEENSC9006096

The mass of planet Jupiter is 1.9 x 1027 kg and that of the sun is 1.99 x 1030 kg. The mean distance of the Jupiter from the sun is 7.8 x 1011 m. Calculate the gravitational force which the sun exerts on Jupiter.

Solution

Given comma

Mass space of space Sun comma space straight M space equals space 1.99 space cross times space 10 to the power of 30 kg

Mass space of space Jupiter comma space straight m space equals space 1.9 space cross times space 10 to the power of 27 kg

Mean space distance space between space straight b divided by straight w space jupiter space and space Sun comma space straight r space equals space 7.8 space cross times space 10 to the power of 11 space straight m

Gravitational space constant comma space straight G space equals 6.67 space cross times space 10 to the power of negative 11 end exponent space Nm squared divided by kg squared

therefore space space space space straight F space equals space GMm over straight r squared

space space space space space space space space space space space equals space fraction numerator 6.67 space cross times space 10 to the power of negative 11 end exponent cross times space 1.99 space cross times space 10 to the power of 30 space cross times space 1.9 space cross times space 10 to the power of 27 over denominator left parenthesis 7.8 space cross times space 10 to the power of 11 right parenthesis squared end fraction

space space space space space space space space space space space equals space 4.145 space cross times space 10 to the power of 23 straight N.
 
F is the gravitaional force which the Sun exerts on Jupiter. 

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