Question
A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity.
Solution
Given, a stone is released from the top of a tower.
Initial velocity, u = 0 m/s
Acceleration due to gravity, g = -9.8 m/s2
Distance covered by the ball during the course of it's motion = 19.6 m
Now, usign the equation of motion,
v2 - u2 = 2ags
We have,
v2 - 02 = 2 * (-9.8) * (-19.6)
i.e., v2 - 02 = (19.6)2
i.e., v = - 19.6 m/s
The negative sign indicates that the velocity is acting in the downward direction
