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Matter In Our Surroundings

Question
CBSEENSC9005739

A train is travelling at a speed of 90 km/h. The brakes are applied so as to produce a uniform acceleration of - 0.5 m/s2. Find how far the train goes before it stops?

Solution
Here comma space
I n i t i a l space v e l o c i t y space o f space t r a i n comma space straight u space equals space 90 space km divided by straight h space
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 90 space cross times space 1000 space straight m over denominator 3600 space straight s end fraction space
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 25 space straight m divided by straight s

Acceleration comma space straight a space equals space minus 0.5 space straight m divided by straight s squared

Final space velocity comma space straight v space equals space 0

U sin g space e q u a t i o n space o f space m o t i o n comma space space straight v squared space minus space straight u squared space equals space 2 as comma space w e space h a v e

space space space 0 squared space minus space 25 squared space equals space 2 space cross times space left parenthesis negative 0.5 space right parenthesis straight s space space space

space space space straight s space equals space fraction numerator 625 over denominator 2 space cross times 0.5 end fraction space equals 625 space straight m
Therefore, distance travelled by the train before it stops = 625 m