+91-8076753736 support@wiredfaculty.com
logo
logo

Sponsor Area

Application Of Integrals

Question
CBSEENMA12036225
Wired Faculty App

The parabolas y2 = 4x and x2 = 4y divide the square region bounded by the lines x = 4, y = 4 and the coordinate axes. If S1, S2, S3 are respectively the areas of these parts numbered from top to bottom; then S1 : S2: S3 is

  • 1 : 2 : 1

  • 1 : 2 : 3

  • 2 : 1 : 2

  • 1 : 1 : 1

Solution

D.

1 : 1 : 1

y2 = 4x and x2 = 4y are symmetric about line y = x
space straight y space equals straight x space is space integral subscript 0 superscript 4 space left parenthesis 2 space square root of straight x minus space straight x right parenthesis space dx space equals space 8 over 3 rightwards double arrow space straight A subscript straight s subscript 2 end subscript space equals space 16 over 3 space and space straight A subscript straight s subscript 1 end subscript space equals space straight A subscript straight s subscript 3 end subscript space equals space 16 over 3 rightwards double arrow space straight A subscript straight s subscript 1 end subscript colon space straight A subscript straight s subscript 2 end subscript space colon space straight A subscript straight s subscript 3 end subscript space colon colon space 1 colon 1 colon 1

Some More Questions From Application of Integrals Chapter

A small firm manufactures necklaces and bracelets. The total number of necklaces and bracelets that it can handle per day is at most 24. It takes one hour to make a bracelet and half an hour to make a necklace. The maximum number of hours available per day is 16. If the profit on a necklace is ` 100 and that on a bracelet is ` 300. Formulate on L.P.P. for finding how many of each should be produced daily to maximize the profit? It is being given that at least one of each must be produced.

Solve the following L.P.P. graphically :
Minimise Z = 5x + 10y
Subject to x + 2y ≤ 120
Constraints x + y ≥ 60
x – 2y ≥ 0
and x, y ≥ 0

The line L1: y = x = 0 and L2: 2x + y = 0 intersect the line L3: y + 2 = 0 at P and Q respectively. The bisectorof the acute angle between L1 and L2 intersects L3 at R.
Statement-1: The ratio PR: RQ equals 2√2:√5
Statement-2: In any triangle, the bisector of an angle divides the triangle into two similar triangles.

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation