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Application Of Integrals

Question
CBSEENMA12036260

limit as straight n rightwards arrow infinity of space sum from straight r equals 1 to straight n of space 1 over straight n straight e to the power of straight r over straight n end exponent space is space
  • e

  • e+1

  • e-1
  • 1-e

Solution

C.

e-1
limit as straight x rightwards arrow infinity of space sum from straight r space equals 1 to straight n of space 1 over straight n straight e to the power of straight r divided by straight n end exponent
space equals space integral subscript 0 superscript 1 space straight e to the power of straight x space dx
space equals space open square brackets straight e to the power of straight x close square brackets subscript 0 superscript 1
straight e minus 1