-->

Application Of Integrals

Question
CBSEENMA12036193

The area enclosed between the curves y2 = x and y = |x| is

  • 2/3

  • 1/3

  • 1/6

  • 3

Solution

C.

1/6


straight A space equals space integral subscript 0 superscript 1 left parenthesis square root of straight x minus straight x right parenthesis dx
space equals space open square brackets 2 over 3 straight x to the power of 3 divided by 2 end exponent minus straight x squared over 2 close square brackets subscript 0 superscript 1
space equals space 2 over 3 space minus 1 half space equals space 1 over 6