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Application Of Integrals

Question
CBSEENMA12035961

Using integration find the area of the triangular region whose sides have equations  y=2x+1,  y=3x+1  and  x=4.

Solution

Equations of the lines are   y = 2 x + 1,    y = 3 x + 1     and   x = 4.

Let  y1 = 2 x + 1,   y2 = 3 x + 1 

Now area of the triangle bounded by the given lines,

=  y2 - y1 04 dx=  3 x + 1  -  2 x + 1  04 dx= x04 dx= 12  x2 04= 12  42 - 02 = 12 × 16

= 8 sq. units

Thus, the area of the required triangular region is  8 square units