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Application Of Integrals

Question
CBSEENMA12035823

Using integration, find the area of the region in the first quadrant enclosed by the x-axis, the line y = x and the circle x2 + y2 =32

Solution

Put y = x in  x2 + y2 =32

∴ x2 + x2 = 32

2x2 = 32

x2 =16

x = 4

A = 04 yline dx + 432ycircle dxA = 04 x dx + 432 (32 -x2dx = x2204 + 432 (32)2 - x2 dx = (8) + x232 - x2 + 322 sin-1x3232 = (8) + 0 + 16 x π2 - 216 + 16 sin-1432 8 +8π - 8 - 16 sin-1 12 = 8π -16 x π4 = 8π- 4π = 4π sq units