Sponsor Area
Conic Section
Question
In an ellipse, the distance between its foci is 6 and minor axis is 8. Then its eccentricity is
-
3/5
-
1/5
-
2/5
-
4/5
Solution
A.
3/5
2ae = 6 ⇒ ae = 3
2b = 8 ⇒ b = 4
b2= a2(1 − e2)
16 = a2 − a2e2
a2= 16 + 9 = 25
a = 5
∴e = 3/a = 3/5
Sponsor Area
Mock Test Series
Mock Test Series



