Question

The ellipse x²+ 4y²= 4 is inscribed in a rectangle aligned with the coordinate axes, which in turn is inscribed in another ellipse that passes through the point (4, 0). Then the equation of the ellipse is

x²+ 16y²= 16

x²+ 12y²= 16

4x²+ 48y²= 48

4x²+ 64y²= 48

Solution

x²+ 12y²= 16

straight x squared over 16 space plus straight y squared over straight b squared space equals space 1 It space passes space through space left parenthesis 2 comma 1 right parenthesis So space 4 over 16 space plus 1 over straight b squared space equals space 1 1 over straight b squared space equals space 3 over 4 straight b squared space equals space 4 over 3 rightwards double arrow space straight x squared space plus space 12 straight y squared space equals space 16

Some More Questions From Conic Section Chapter

For Daily Free Study Material Join wiredfaculty