Question
In how many ways can three prizes be given to 10 boys when a boy may receive any number of prizes?
Solution
The number of ways in which first prize may be given = 10.
Number of ways in which second prize may be given = 10.
Number of ways in which third prize may be given = 10.
∴ By fundamental principle of counting, the total number of permutations
= 10 x 10 x 10 = 1000
ALTERNATIVELY : n = 10, r = 3
Number of permutations (for repeat case) = nr = 103 = 1000.
