Question
Determine K, so that K + 2, 4K – 6 and 3K – 2 are three consecutive terms of an A.P.
Solution
Since K + 2, 4K - 6 and 3K - 2 are three consecutive terms of an A.P.
∴ (4K - 6) - (K + 2) = (3K - 2) - (4K - 6)
or 4K - 6 - K - 2 = 3K - 2 - 4K + 6 or 3K - 8 = -K + 4
or 4K = 12 or K = 3
