Question
A bag contains 5 different black balls and 6 different red balls. Determine the number of ways in which 2 black and 3 red balls can be selected?
Solution
Number of black balls = 5
Number of black balls to be selected = 2 Number of selections =
...(i)
Number of red balls = 6
Number of red balls to be selected = 3 Number of selections =
Hence, from (i) and (ii), by fundamental principle of counting, the required number of selections
= 10 x 20 = 200.