Permutations And Combinations


In how many ways can 10 students in a class be seated so that the most intelligent student and the weakest student never sit together?


Solution not provided.
Ans. 8 x 9!

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Some More Questions From Permutations and Combinations Chapter

Determine K, so that K + 2, 4K – 6 and 3K – 2 are three consecutive terms of an A.P.