Permutations And Combinations

Question
CBSEENMA11014037

How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is not allowed.


Solution

Number of ways in which place (x) can be filled = 5
                                           m = 5
Number of ways in which place (y) can be filled = 4      (∵ Repetition is not allowed)
                                           n = 4
Number of ways in which place (z) can be filled = 3      (∵ Repetition is not allowed)
                                           p = 3
∴ By fundamental principle of counting, the total number of 3 digit numbers formed
                                         = m x n x p = 5 x 4 x 3 = 60.

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Some More Questions From Permutations and Combinations Chapter

Determine K, so that K + 2, 4K – 6 and 3K – 2 are three consecutive terms of an A.P.