Question

Find a relation between x and y such that the point (x, y) is equidistant from the point (3, 6) and (-3, 4).

Solution

Let P(x, y), A(3, 6) and B(-3, 4) be the given points.
It is given that, AP = BP

Squaring both side, we get
x² + y² - 6x - 12y + 45
= x² + y² + 6x - 8y + 25
⇒- 6x - 6x - 12y + 8v + 45 - 25 = 0
⇒    - 12x - 4y + 20 = 0
⇒    - 4(3x + y - 5) = 0
⇒    3x + y - 5 = 0.

Some More Questions From Introduction to Trigonometry Chapter

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Introduction To Trigonometry

Find a relation between x and y such that the point (x, y) is equidistant from the point (3, 6) and (-3, 4).

Some More Questions From Introduction to Trigonometry Chapter

Find the values of y for which the distance between the points P(2, – 3) and Q(10, y) is 10 units.

Find a relation between x and y such that the point (x, y) is equidistant from the point (3, 6) and (-3, 4).

Find the coordinates of the points of trisection of the line segment joining (4, –1) and (–2, –3).

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