Find the HCF of 96 and 404 by the prime factorisation method. Hence, Find their LCM.

Solution

Since 96 = 2 × 2 × 2 × 2 × 2 × 3

= 2^s × 3 and 404 = 2 × 2 × 101 = 2² × 101

∴ LCM = Product of each prime factor with highest power

= 2^s × 3 × 101 = 9696

i.e., LCM (96, 404) = 9696

HCF Product of common prime factors with lowest powers

= 2² = 4

We know that,

HCF (a. b) × LCM (a,b) = a × b

⇒ HCF (96, 404) × LMC (96, 404) = 96 × 404

⇒ LCM (96, 404)
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Some More Questions From Real Numbers Chapter

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Real Numbers

Find the HCF of 96 and 404 by the prime factorisation method. Hence, Find their LCM.

Some More Questions From Real Numbers Chapter

Express each number as a product of its prime factors: (i) 140

Express each number as a product of its prime factors: (ii) 156

Express each number as a product of its prime factors: (ii) 156 (iii) 3825 (iv) 5005 (v) 7429

Express each number as a product of its prime factors: (iv) 5005

Express each number as a product of its prime factors: (v) 7429

Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. (i) 26 and 91

Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. (ii) 510 and 92

Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. (iii) 336 and 54

Find the LCM and HCF of the following integers by applying the prime factorisation method. (i) 12, 15 and 21

Find the LCM and HCF of the following integers by applying the prime factorisation method. (ii) 17, 23 and 29

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