Question
CBSEENMA9003826

Find the mean of each of the following distributions :

(i)

xi

10

15

20

25

30

35

40

Total

fi

4

6

8

18

6

5

3

50

(ii)

xi

12

13

14

15

16

17

18

Total

fi

1

3

4

8

10

3

1

30

(iii)

xi

50

75

100

125

150

175

200

Total

fi

12

18

50

70

25

15

10

200

Solution

(i)

xi

fi

fixi

10

4

40

15

6

90

20

8

160

25

it

450

30

6

180

35

5

175

40

3

120

Total

50

1215


Mean space equals space fraction numerator sum straight f subscript straight i straight x subscript straight i over denominator sum straight f subscript straight i straight x subscript straight i end fraction equals 1215 over 50 equals 24.3

xi

fi

fixi

12

1

12

13

3

39

14

4

56

15

8

120

16

10

160

17

3

51

18

1

18

Total

30

456


Mean equals fraction numerator sum straight f subscript straight i straight x subscript straight i over denominator sum straight f subscript straight i end fraction equals 456 over 30 equals 15.2

(iii)

xi

fi

fixi

50

12

600

75

18

1350

100

50

5000

125

70

8750

150

25

3750

175

15

2625

200

10

2000

Total

200

24075


Mean equals fraction numerator sum straight f subscript straight i straight x subscript straight i over denominator sum straight f subscript straight i end fraction equals 24075 over 200 equals 120.375

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