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Probability

Question
CBSEENMA9003537

The difference between outside and inside surface of a cylindrical metallic pipe 14 cm long is 44 cm2. If the pipe is made of 99 cm3 of metal, find the outer and inner radii of the pipe.

Solution
Let the outer and inner radii of the pipe be R cm and r cm respectively. Then,
             2 πR left parenthesis 14 right parenthesis minus 2 πr left parenthesis 14 right parenthesis equals 44
rightwards double arrow space space space space space space 28 straight pi space left parenthesis straight R minus straight r right parenthesis equals 44
rightwards double arrow space space space space space space 28 cross times 22 over 7 left parenthesis straight R minus straight r right parenthesis equals 44
rightwards double arrow     straight R minus straight r equals 1 half space space space space space space space space space space... left parenthesis 1 right parenthesis
and,    πR squared left parenthesis 14 right parenthesis minus πr squared left parenthesis 14 right parenthesis equals 99
rightwards double arrow space space space space space space 14 straight pi space left parenthesis straight R squared minus straight r squared right parenthesis equals 99
rightwards double arrow space space space space space space space space space 14 cross times 22 over 7 left parenthesis straight R squared minus straight r squared right parenthesis space equals space 99
rightwards double arrow space space space space space space space space space left parenthesis straight R plus straight r right parenthesis left parenthesis straight R minus straight r right parenthesis equals 9 over 4
rightwards double arrow space space space space space space space space space space left parenthesis straight R plus straight r right parenthesis 1 half equals 9 over 4 space space space space space space vertical line space From space left parenthesis straight i right parenthesis
rightwards double arrow space space space space space space space space space space straight R plus straight r equals 9 over 2 space space space space space space... left parenthesis 2 right parenthesis
Solving (1) and (2), we get
           straight R equals 5 over 2 space cm
straight r space equals space 2 space cm