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Probability

Question
CBSEENMA9003719

The volumes of two spheres are in the ratio 64 : 27. Find the difference of their surface areas, if the sum of their radii is 7 cm.

Solution
Let the radii of the two spheres be r1 cm and r2 cm respectively. Then,
straight v subscript 1 over straight v subscript 2 equals fraction numerator begin display style 4 over 3 end style πr subscript 1 cubed over denominator begin display style 4 over 3 end style πr subscript 2 cubed end fraction equals 64 over 27
rightwards double arrow space space open parentheses r subscript 1 over r subscript 2 close parentheses cubed equals open parentheses 4 over 3 close parentheses cubed
rightwards double arrow space space space r subscript 1 over r subscript 2 equals 4 over 3 space space space space space space space space space space space space space space space... left parenthesis 1 right parenthesis
straight r subscript 1 plus straight r subscript 2 equals 7 space cm space space space space space space space space space space space space space space space space... left parenthesis 2 right parenthesis
From (1) and (2)
     straight r subscript 1 space equals space 4 space cm
straight r subscript 2 space equals space 3 space cm
therefore  Difference of their surface areas
           equals 4 πr subscript 1 squared minus 4 πr subscript 2 squared
equals space 4 πr left parenthesis straight r subscript 1 squared minus straight r subscript 2 squared right parenthesis
equals space 4 straight pi space left parenthesis 4 squared minus 3 squared right parenthesis
equals space 4 straight pi left parenthesis 16 minus 9 right parenthesis
equals 4.22 over 7.7
equals space 88 space cm squared

Some More Questions From Probability Chapter

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