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Probability

Question
CBSEENMA9003395

 A metal pipe is 77 cm long. The inner diameter of a cross section is 4 cm, the outer diameter being 4.4 cm. Find its

(i)     inner curved surface area,
(ii)    outer curved surface area,
(iii)   total surface area.

Solution

h = 77 cm
2r = 4 cm

⇒    r = 2 cm
2R = 4.4 cm
⇒    R = 2.2 cm

 (i) Inner curved surface area = 2 πrh
            equals 2 cross times 22 over 7 cross times 2 cross times 77 equals 968 space cm squared
(ii) Outer curved surface area = 2 πRh
            equals 2 cross times 22 over 7 cross times 2.2 cross times 77 equals 1064.8 space cm squared
(iii) Total surface area
           equals 2 πRh plus 2 πrh plus 2 straight pi left parenthesis straight R squared minus straight r squared right parenthesis
equals space 1064.8 plus 2 cross times 22 over 7 cross times 2 cross times 77 plus 2 cross times 22 over 7 cross times left curly bracket left parenthesis 2.2 right parenthesis squared minus left parenthesis 2 right parenthesis squared right curly bracket
equals space 1064.8 plus 968 plus 2 cross times 22 over 7 cross times left parenthesis 4.84 minus 4 right parenthesis
equals 1064.8 plus 968 plus 2 cross times 22 over 7 cross times 0.84
equals space 1064.8 plus 968 plus 5.28 equals 2038.08 space cm squared