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Let the length and the breadth of the room be 4x m and x m respectively.
Area of the four walls of the room = 2(l + b) h
= 2(4x + x) 5 = 50 x m2
Cost of papering the four walls of the room @ 70 paise per square metre
= र 50x x 0.70 = र 35x According to the question,
35x = 157.50
∴ Breadth of the room = 4.5 m
∴ Length of the room = 4 x 4.5 m = 18 m.
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Parveen wanted to make a temporary shelter for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m, with base dimensions 4 m × 3 m?
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