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Areas Of Parallelograms And Triangles

Question
CBSEENMA9002605

If the bisector of the vertical angle of a triangle bisects the base of the triangle, then prove that the triangle is isosceles.

Solution

Given: A ∆ABC in which the bisector of the vertical angle ∠BAC bisects the base BC, i.e., BD = CD

To Prove: ∆ABC is isosceles

Construction: Produce AD to E such that AD = DE. Join EC.
Proof: In ∆ADB and ∆EDC,
BD = CD    | Given
AD = ED    | By construction
∠ADB = ∠EDC
| Vertically opposite angles
∴ ∆ADB ≅ ∆EDC
| SAS congruence rule ∴ AB = EC    ...(1) | CPCT
and    ∠BAD = ∠CED    | CPCT
But ∠BAD = ∠CAD    | Given
∴ ∠CAD = ∠CED
∴ AC = CE    ...(2)
| Sides opposite to equal angles of a triangle are equal
From (1) and (2),
AB = AC
∴ ∆ABC is isosceles.