Question
The taxi fare in a city is as follows: For the first kilometre, the fare is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw its graph.
Solution
Total distance covered = x km
Total fare = Rs y
Fare for the first kilometre = Rs 8
Subsequent distance = (x – 1) km
Fare for the subsequent distance = Rs 5(x – 1)
According to the question,
y = 8 + 5 (x – 1)
⇒ y = 8 + 5x – 5
⇒ y = 5x + 3
Table of solutions
|
x |
0 |
1 |
|
y |
3 |
8 |
We plot the points (0, 3) and (1, 8) on the graph paper and join the same by a ruler to get the line which is the graph of the equation y = 5x + 3.
