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Playing With Numbers

Question
CBSEENMA8002733

Check what the result would have been if Minakshi had chosen the numbers shown below. In each case keep a record of the quotient obtained at the end.

Solution

1. 132                      Chosen number = 132
                            Reversed number = 231
                                     Difference  = 231 - 132
                                                    = 99
We have                          99 + 99 = 1, remainder = 0
2. 469                       Chosen  number = 469
                              Reversed number = 964
                                       Difference = 964 - 469 = 495
We have                           495 + 99 = 5, remainder = 0

3.                             Chosen  number = 737
                             Reversed number  = 737
                          We have dirrerence = 737 - 737 = 0
                                              0 + 99 = 0, remainder = 0
4.                              Chosen number   = 901
                               Reversed number  = 109
                                        Differende  = 901 - 109
                                                       =  792
         We have               792 + 99 = 8, remainder = 0
Forming three digit number with given three dgits.