Question
A segment of DNA has 120 adenine and 120 cytosine bases. The total number of nucleotides present in the segment is
60
240
120
480
Solution
D.
480
According to Charagff's rules, the amount of adenine is always equal to that of thymine, and the amount of guanine is always equal to that of cytosine.
A = T(120)
G = C(120)
The total number of nucleotides would be 120 x 4 = 480