Question
In which of the following compounds, sulphur show maximum oxidation number?
H2SO4
SO3
H2S2O7
All have same oxidation number for sulphur
Solution
D.
All have same oxidation number for sulphur
All have same oxidation number for sulphate i.e + 6
(i) oxidation number of S is
H2SO4 = +2 +x -8 = 0
Therefore, x = +6
(ii) Oxidation number of S is SO3 = x - 6 = 0
Therefore, x = 6
(iii) Oxidation number of S in H2S2O7
= 2 + 2x - 14 = 0
2x = + 12
x = +6
