Question
In the electrochemical cell :
Zn|ZnSO4(0.01M)||CuSO4(1.0 M)|Cu, the emf of this Daniel cell is E1. When the concentration of ZnSO4 is changed to 1.0 M and that of CuSO4 changed to 0.01 M, the emf changes to E2. From the following, which one is the relationship between E1 and E2?
(Given, RT/F= 0.059)
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E1= E2
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E1< E2
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E1> E2
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E2= 0 ≠ E1
Solution
C.
E1> E2
Zn|ZnSO4(0.01 M)||CuSO4(1.0 M)|Cu
