Question
Combustion of glucose takes place according to the equation.
C6H12O6 + 6O2 → 6CO2 + 6H2O
Δ = - 72 k-cal
The energy required for combustion of 1.6 g of glucose is
0.064 kcal
0.64 kCal
6.4 kcal
64 kcal
Solution
B.
0.64 kCal
Molar mass of C6H12O6 = 180 g mol-1
∵ 180 g of glucose require energy = 72 kcal
∴ 1.6 g of glucose require energy = 72 x 1.6/180
= 0.64 k cal
