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Solutions

Question
CBSEENCH12011468

The solubility of BaSO4 in water is 2.42 × 10–3 gL–1 at 298 K. The value of its solubility product (Ksp) will be
(Given the molar mass of BaSO4 = 233 g mol–1)

  • 1.08 x 10-10 mol2L-2

  • 1.08 x 10-12 mol2L-2

  • 1.08 x 10-8 mol2L-2

  • 1.08 x 10-14 mol2L-2

Solution

A.

1.08 x 10-10 mol2L-2

BaSO4 (s)  Ba2+ (aq) (s)  + SO42- (aq)(s)Solubility of BaSO4, s = 2.42 x 10-3233 (mol L-1) = 1.04 x 10-5 (mol L-1)Ksp = [Ba2+][SO42-] = s2 = (1.04 x 10-5)2 = 1.08 x 10-10 mol2 L-2