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Coordination Compounds

Question
CBSEENCH12011464
Wired Faculty App

The geometry and magnetic behaviour of the complex [Ni(CO)4] are

  • Square planar geometry and diamagnetic

  • Tetrahedral geometry and diamagnetic

  • Tetrahedral geometry and paramagnetic

  • Square planar geometry and paramagnetic

Solution

B.

Tetrahedral geometry and diamagnetic

Ni(28) : [Ar]3d8 4s2
∵CO is a strong field ligand, so unpaired electrons get paired. Hence, the configuration would be.

For, four ‘CO’-ligands hybridisation would be sp3 and thus the complex would be diamagnetic and of tetrahedral geometry.

Some More Questions From Coordination Compounds Chapter

Write the formula for the following coordination compound:
Dichloridobis(ethane-1, 2-diamine)platinum(lV) nitrate.

Write the formula for the following coordination compound:
Iron(III) hexacyanidoferrate(II)

Write the IUPAC names of the following coordination compounds:
(i) [Co(NH3)6]Cl3
(ii) [Co(NH3)5Cl]Cl2
(iii) K3[Fe(CN)6]
(iv) K3[Fe(C2O4)3]
(v) K2[PdCl4]
(vi) [Pt(NH3)2Cl(NH2CH3)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i)    K[Cr(H2O)2(C2O4)2],                      (ii) [Co(en)3Cl3,
(iii) [Co(NH3)5(NO2)]|NO3]2,                 (iv) [Pt(NH3)(H2O)Cl2]

Explain on the basis of valence bond theory that [Ni(CN)4]2–  ion with square planar is diamagnetic and the [NiCl4]2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)4,]2– ion.

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