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Electrochemistry

Question
CBSEENCH12011307
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The equivalent conductance of M/32 solution of weak monobasic acid is 8.0 ohm-cm2 and at infinite dilution is 400 ohm-cm2. The dissociation constant of this acid is

  • 1.25 x 10-5

  • 1.25 x 10-6

  • 6.25 x 10-4

  • 1.25 x 10-4

Solution

A.

1.25 x 10-5

Degree of dissociation, 
alpha space equals straight capital lambda to the power of straight c over straight capital lambda to the power of infinity
Where,  straight capital lambda to the power of straight cand  straight capital lambda to the power of infinity are equivalent conductances at a given concentration and at infinite dilution respectively.
straight alpha space equals space fraction numerator 8.0 over denominator 400 end fraction space equals space 2 space straight x space 10 to the power of negative 2 end exponent
From Ostwald's dilution law (for weak monobasic acid)
straight K subscript straight a space equals fraction numerator Cα squared over denominator left parenthesis 1 minus straight alpha right parenthesis end fraction equals space Cα squared space space space space space space space left parenthesis because space 1 space greater than greater than straight alpha right parenthesis equals space 1 over 32 left parenthesis 2 space straight x space 10 to the power of negative 2 end exponent right parenthesis squared equals space 1.25 space straight x space 10 to the power of negative 5 end exponent

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