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Electrochemistry

Question
CBSEENCH12011376
Wired Faculty App

The equilibrium constant of the reaction:

Cu (s) + 2 Ag+ (aq) →  Cu2+ (aq) + 2 Ag (s);

Eo = 0.46 V at 298 K

  • 2.4 x 1010

  • 2.0 x 1010

  • 4.0 x 1010

  • 4.0 x 1015

Solution

D.

4.0 x 1015

Cu (s) + 2 Ag+ (aq) →  Cu2+ (aq) + 2 Ag (s)
Eo = 0.46 V at 298 K

RT space ln space straight K space space equals space nFE to the power of straight o In space straight K space equals space nFE to the power of straight o over RT space equals fraction numerator space 2 space straight x space 0.46 over denominator 0.0591 end fraction space straight K space equals space 4 space straight x space 10 to the power of 15

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