Question
Consider the following relations for emf of an electrochemical cell
A) Emf of cell = (oxidation potential of anode) - (reduction potential of cathode)
B) Emf of cell = (oxidation potential of anode) - ( reducation potential of cathode)
C) Emf of cell = (oxidation potential of anode)- (reduction potential of cathode)
D) Emf of cell = (oxidation potential of anode) - (oxidation potential of anode)-(oxidation potential of cathode)
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(C) and (A)
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(A) and (B)
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(C) and (D)
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(B) and (D)
Solution
D.
(B) and (D)
