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Solutions

Question
CBSEENCH12011284

25.3 g of sodium carbonate, Na2CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely molar concentration of sodium ion, Na+ and carbonate ion, CO32- are respectively (Molar mass of Na2CO3 = 106 g mol-1)

  • 0.955 M and 1.910 M

  • 1.910 M and 0.955 M 

  • 1.90 M and 1.910 M 

  • 0.477 M and 0.477 M 

Solution

B.

1.910 M and 0.955 M 

Molarity space equals space fraction numerator number space of space moles space space of space solute over denominator volume space of space solution space left parenthesis in space mL right parenthesis end fraction straight x space 1000
space
equals space fraction numerator 25.3 space straight x space 1000 over denominator 106 space straight x space 250 end fraction space equals space 0.9547 space equals space 0.955 space straight M

Na subscript 2 CO subscript 3 space in space aqueous space solution space remains space dissociated space as

stack Na subscript 2 CO subscript 3 space space with straight x below rightwards arrow space stack 2 Na to the power of plus space with 2 straight x below plus space stack CO subscript 3 superscript 2 minus end superscript with straight x below
Since comma space the space molarity space of space Na subscript 2 CO subscript 3 space is space 0.955 space straight M comma space the space molarity space of space CO subscript 3 superscript 2 minus end superscript space
is space also space 0.955 space straight M space and space that space of space Na to the power of plus space is space 2 space straight x space 0.955 space equals space 1.910 space straight M